We describe the extremal translation invariant stationary (ETIS) states of the facilitated exclusion process on . In this model, all particles on sites with one occupied and one empty neighbor jump at each integer time to the empty neighbor site, and if two particles attempt to jump into the same empty site, we choose one randomly to succeed. The ETIS states are qualitatively different for densities ρ < 1/2, ρ = 1/2, and 1/2 < ρ < 1, but in each density region, we find states that may be grouped into families, each of which is in natural correspondence with the set of all ergodic measures on . For ρ < 1/2, there is one such family, containing all the ergodic states in which the probability of two adjacent occupied sites is zero. For ρ = 1/2, there are two families, in which configurations translate to the left and right, respectively, with constant speed 2. For the high density case, there is a continuum of families. We show that all ETIS states at densities ρ ≤ 1/2 belong to these families and conjecture that also at high density there are no other ETIS states. We also study the possible ETIS states that might occur if the conjecture fails.
I. INTRODUCTION
A facilitated exclusion process, sometimes called a conserved lattice gas, is a model of particles moving on a lattice, usually or a finite portion of it with periodic boundary conditions, in which a particle can jump to a neighboring (empty) site only if another of its neighboring sites is occupied (by a facilitating particle). Many variations of such models have been studied in both the physics and mathematics literature, with (i) different values of the dimension d; (ii) implementations of the dynamics in either continuous time, in which each facilitated particle attempts to jump independently at a certain rate (or equivalently, in a finite system, with random sequential updating), or discrete time, in which all facilitated particles attempt to jump simultaneously, at integer times; and (iii) for d = 1, various distributions, symmetric, partially asymmetric, or totally asymmetric, governing the choice of target site (for d ≥ 2, we are aware of studies only of the symmetric distribution). For the one-dimensional case in continuous time, see Refs. 1–4 for symmetric dynamics, Refs. 5–9 for totally asymmetric dynamics, and Ref. 10 for the general (symmetric and partially or totally asymmetric) case. For the one-dimensional case in discrete time, with totally asymmetric dynamics, see Refs. 11 and 12. For the higher dimensional case in discrete time, see Refs. 13 and 14. Reference 4 studies, in continuous time with symmetric dynamics, the intermediate case in which the lattice is a ladder with two infinite rows.
In this paper, we consider the case of symmetric discrete-time dynamics on the one-dimensional lattice ; so far as we know, we are the first to do so. (In Remark 1.1, we review briefly, for comparison, the situation for one-dimensional continuous time dynamics10). We find a variety of interesting phenomena that do not occur in the continuous-time d = 1 model and have not been reported in studies of the higher-dimensional discrete-time version.
The configuration space of our model is ; if η is a configuration in X, then we say that a site i with η(i) = 1 is occupied by a particle, and a site with η(i) = 0 is unoccupied or empty. The (stochastic) dynamics is defined as follows: if ηt is the configuration at time t, , then each particle in ηt with exactly one occupied neighboring site attempts to jump to its unoccupied neighboring site; the jump takes place unless two particles attempt to jump on the same site, in which case one of them is chosen at random to succeed, with each choice equally likely. ηt+1 is the resulting configuration.
Our goal is to classify the states—probability measures on X—which are translation invariant (TI) and stationary for the Facilitated Simple Symmetric Exclusion Process (F-SSEP) dynamics, the TIS states. Every TIS state is a convex combination of the extremal TIS (ETIS) states, that is, of the TIS states that are not proper convex combinations of others, so it suffices to find the ETIS states. The ETIS states need not be extremal TI (ETI)—i.e., ergodic under translations—but since the particles are neither created nor destroyed, extremality in the class of TIS states suffices to guarantee (see Lemma 2.4) that each ETIS state will be supported on the set Xρ of configurations having particle density ρ for some ρ with 0 ≤ ρ ≤ 1, that is, satisfying
We will say that a TI state has densityρ if it is supported on Xρ. [Note that this condition implies that for each , the expected value of η(i) is ρ but is, in fact, a stronger statement.]
It is convenient to consider also a second particle system on , again evolving in discrete time: the symmetric stack model (SSM). (To our knowledge, this model has not been considered elsewhere.) In this model, there are no restrictions on the number of particles at any site so that the configuration space is , where . We denote stack configurations by boldface letters, and to distinguish explicit stack configurations from F-SSEP particle configurations, we will use italics for the former so that for , we might have n(0) = 2. To specify the evolution of the SSM, let us say that the stack at site i is short if n(i) ≤ 1 and tall otherwise. Then, in the transition from nt to nt+1, either zero or one particle moves along each bond ⟨k, k + 1⟩, either to the left or to the right: if the stacks at k and k + 1 are both short, then no particle moves on the bond; if one is short and one tall, then a particle moves from the tall to the short stack; and if both are tall, then a particle moves from one to the other in a randomly chosen direction, with each direction equally likely.
For the SSM, we again speak of TIS and ETIS states and, for , of states of density , where the latter are those supported on , the set of SSM configurations of density , defined in parallel with (1.1). If the expected value of n(0) is finite in a TI state on , then we say that the state is regular. A TI state on X is called regular if it gives zero probability to the configuration η for which η(i) = 1 for all i.
The SSM is connected with the F-SSEP through a substitution map : if , then ϕ(n) is obtained by replacing each n(i) with a zero followed by n(i) ones. (Such a mapping has also been used to relate exclusion and zero range processes; see, e.g., Refs. 15 and 16.) In Appendix A, we show that this substitution, and members of a large class of similar substitutions, gives rise to a bijection of the regular TI or ETI states of the models related by the substitution. Moreover, we show there that for the particular substitution ϕ above, the bijection Φϕ of the regular TI states is also a bijection from the regular TIS or ETIS states of the SSM to those of the F-SSEP. Thus, for the question of interest here—the nature and classification of the TIS states—the F-SSEP and SSM are essentially equivalent, and we can and will pass freely from one to the other. Note that if n has density , then ϕ(n) has density ; correspondingly, Φϕ carries regular SSM states of density to regular F-SSEP states of density ρ.
Recall now that each regular ETIS state is associated with some density ρ in the F-SSEP or equivalently in the SSM. The classification of the ETIS states of the models is qualitatively different in the three density regions 0 ≤ ρ < 1/2, ρ = 1/2, and 1/2 < ρ < 1 or, equivalently, , , and . The states in the first two of these regions are, of course, all regular.
Consider first the low density region. The set of ETIS states of the SSM with is precisely the set of ETI states supported on , the set of frozen SSM configurations for which every stack has height zero or one (note that, in fact, ). For the F-SSEP, the corresponding result is that the ETIS states are the ETI states supported on the set F of frozen F-SSEP configurations: those in which no two adjacent sites are occupied and, hence, no particle jumps are possible.
When in the SSM (ρ = 1/2 in the F-SSEP), there are two families of ETIS states in each model; these describe patterns moving to the left or to the right, respectively, with speed 1 in the SSM and speed 2 in the F-SSEP. In the SSM, the left-moving family consists of all ETI states supported on , the set of configurations in which no stack has height more than 2, a stack of height 2 can be followed only by one of height 0, and a stack of height 0 can be preceded only by one of height 2. Similarly, the right-moving family consists of the ETI states on , the spatial reflection of . Two states belong to both families: the state (which is also one of the low-density states of the previous paragraph) supported on the single configuration in which all stacks have height 1 and the state supported with equal probability on the two configurations in which stacks of height 0 and 2 alternate. The left- and right-moving families in the F-SSEP are obtained from those of the SSM via the map Φϕ.
All TIS states in the high density region of the SSM, , are supported on , the set of configurations for which no two adjacent sites both have short stacks. On , the dynamics preserves the parity of each stack height so that if for σ ∈ X, we let be the set of configurations n for which n(i) has parity (−1)σ(i), then each is invariant for the dynamics. (In these circumstances, we call σ a parity sequence.)
Let e be the parity sequence with e(i) = 0 for all i so that is the set of configurations for which each stack height is even and there are no adjacent zeros. For each , we find an ETIS state on of density , which we conjecture to be unique: if , then is the state described above, while if , then is a Gibbs state for an interaction that is simply a one-body potential together with the constraints—hard-core and evenness—implicit in . Further, for each such , we obtain from a family of regular ETIS states on and show that if the conjecture mentioned above holds, then these are all such states. Specifically, for each and each ETI state λ on X, there is an ETIS state for the SSM; has the distribution of η + σ (pointwise addition), where η has distribution , σ has distribution λ, and η and σ are independent. Note that if λ has density κ, then has density . The corresponding families for the F-SSEP are obtained via the map Φϕ.
A discussion of the TIS states of the continuous-time version of the model, generalized to include an asymmetry in the jumps, was given in Ref. 10. The asymmetry is controlled by a parameter p ∈ [0, 1]: a particle at site jumps to site i + 1 (respectively, i − 1) with rate p (respectively, 1 − p), provided that site i − 1 (respectively, i + 1) is occupied and site i + 1 (respectively, i − 1) is empty. For ρ < 1/2, the TIS states are, as for the current model, just the TI states supported on F, but for the continuous-time model, it was possible to determine the limiting state when the initial state μ0 is Bernoulli; rather surprisingly, is independent of p. ( is also11,12 the limiting state, with initial state μ0, under totally asymmetric discrete-time dynamics.) For ρ = 1/2, the unique TIS state is supported with equal probability on the two configurations in which occupied and empty sites alternate. For each ρ > 1/2, there is again a unique TIS state, the Gibbs state for a particle system in which the only interaction is an exclusion rule forbidding adjacent empty sites; the uniqueness was established via a coupling of the model with the usual asymmetric simple exclusion process.
II. PRELIMINARY CONSIDERATIONS
We here introduce some further notation and provide some simple results for the F-SSEP and SSM models, often speaking in terms of the F-SSEP with the understanding that parallel notation will be used, and similar results hold, for the SSM. Let us mention several pieces of general notation: for any sets A and B, function f: A → B, and measure λ on A, we let f*λ be the measure on B with (f*λ)(C) = λ(f−1(C)); moreover, if , we let λ(f) = ∫Af dλ denote the expected value of f under λ. When C ⊂ B, we let 1C: B → {0, 1} denote the indicator function of the set C. If S is a finite set, then |S| denotes the size of S.
Recall from Sec. I that the configuration spaces for these models are and , respectively, with η ∈ X and denoting configurations. For η ∈ X and with j ≤ k, we let η(j: k) = (η(i))j≤i≤k denote the portion of the configuration η lying between sites j and k (inclusive). We will occasionally use string notation for configurations or partial configurations, writing, for example, η(0:4) = η(0)⋯η(4) = 01101 = 01201. τ: X → X (or ) denotes the translation operator: if η ∈ X, then (τη)(i) = η(i − 1); if f is any function on X, then τf(η) = f(τ−1η); and if μ is a (Borel) measure on X, then τ acts on μ via τ*.
It will sometimes be convenient to associate to each F-SSEP configuration η ∈ X a height profile , which, in the usual convention, rises by one unit when η(i) = 0 and sinks by one unit when η(i) = 1. Specifically,
We do not introduce height profiles for SSM configurations.
From the somewhat informal description of the dynamics of the models given in Sec. I, it is straightforward but tedious to specify, for a configuration η ∈ X and a measurable subset A ⊂ X, the transition kernel Q(η, A) of the F-SSEP Markov process, or similarly the kernel for the SSM model. We omit the details. A measure μ on X is stationary if μ = μQ; here, (μQ)(A) = ∫XQ(·, A) dμ [we also write μQn ≔ (μQn−1)Q for n ≥ 2].
In the remainder of this paper, we will consider primarily regular (see Sec. I) states on X and ; the sets of regular TI, ETI, TIS, and ETIS states for the F-SSEP are denoted by , , , and , respectively. We write similarly , etc., as well as , , etc., for A ⊂ X or TI sets. As a consequence of the results of Appendix A (see also the discussion of Sec. I), we have immediately the following theorem:
There exists a bijection, , arising from the substitution map ϕ defined in Sec. 1I, which satisfies , , and . Φϕ carries states of density to states of density . Moreover, if is TI, then there is a similarly defined bijection from to , etc., where A is the minimal TI subset of X containing .
Since we are studying stationary states, it is natural to introduce the set of space–time F-SSEP configurations ; a state that is stationary for the dynamics induces a “path measure” on X2, invariant under vertical translation, which we denote Pμ. and denote the corresponding SSM quantities.
In Secs. III–V, we will describe all ETIS states for the two models. As indicated in Sec. I, these fall into certain natural groups, which we will call λ-families. In this context, we write for the set of ergodic TI measures on X [in fact, , but the special role that this space plays here motivates a special symbol].
A λ-family is a collection of ETIS states for either the SSM or the F-SSEP, which is bijectively equivalent (with a “natural” bijection) to . We think of as indexing the λ-family, and let denote a typical index. We will typically write and for λ-families for the SSM and F-SSEP, respectively, with * being a subscript distinguishing the various families and with . and are the corresponding indexing bijections.
Certain simple spatially-periodic configurations and related states, some already mentioned in Sec. I, will play a special role in our discussions. Let be the configurations with n(1)(i) = 1 and n(2)(i) = (1 + (−1)i) for all i; in Sec. I, we introduced the states defined by , . The corresponding states μ(1) = Φϕ(μ(1)), μ(2) = Φϕ(μ(2)) are given by
where η(1) ∈ X is the period-two configuration with η(1)(1:2) = 10 and η(2) ∈ X is the period-four configuration with η(2)(1:4) = 1100. It is easy to check directly that and are ETIS states for the SSM, as are μ(1) and μ(2) for the F-SSEP.
We conclude this section with three general results; we state these for the F-SSEP, but the obvious translations to the SSM also hold. Recall from Sec. I that we say that a state has density ρ if it is supported on the space Xρ [see (1.1)].
Every ETIS state has a definite density ρ and satisfies either μ(F) = 0 or μ(F) = 1.
We next give a lemma which shows that a connected portion of an F-SSEP configuration, other than possibly a single 1 at some site, cannot be frozen unless the entire configuration is.
Let satisfy μ(F) = 0. Suppose that is an interval, that θ ∈ {0, 1}I, and that either |I| ≥ 2 or I = {i} and θ(i) = 0. Then, .
We remark that the possibility , θ(i) = 1 for all i, an apparent counterexample to Lemma 2.5, is forbidden by the regularity of μ.
Let A, B, C ⊂ X2 denote the sets of space–time histories ξ such that, respectively, ξt(0) = 0 for all t [we write ξt(0) ≡ 0], ξt(−1:0) ≡ 01, and ξt(−1:0) ≡ 11, and such that in each case ξt(1) changes infinitely often as t ↗∞. We show that Pμ(A) = Pμ(B) = Pμ(C) = 0; using the translation invariance of μ, translation invariance in time of Pμ, and reflection invariance of the system (although the latter is not really needed), one sees easily that this implies the result.
First, we observe that if ξ ∈ X2 satisfies ξt(0) ≡ 0 and s is such that ξs(1) = 1, then, Pμ-a.s., ξt(1) = 1 for all t ≥ s and so ξ ∉ A. Thus, Pμ(A) = 0. Next, suppose that ξt(−1:0) ≡ 01; if ξs(1) = 1 for some s then, Pμ-a.s., ξs+1(−1) = 1, a contradiction. Thus, Pμ(ξ ∈ B) = 0. Finally, if ξ ∈ C, we define , with 0 ≤ τ0 < τ1 < ⋯, to be the non-negative times satisfying ; τk are well defined on C. Now, ξ ∈ C implies that , and this is possible only if , and moreover, Lk occurs, where Lk is the event that when two particles attempt at time τk to jump to site 1, it is the leftward jump that succeeds. Given C, the Lk are independent events, each with probability 1/2, so that Pμ(C) = 0.■
Finally, we give a result showing that non-frozen TIS states cannot have too large a local density of 0’s.
Suppose that satisfies μ(F) = 0. Then, we have the following:
μ-a.s., no configuration contains three consecutive 0’s.
μ-a.s., the height profile hη of the configuration η does not increase by more than two units over any interval.
Elementary analysis of the dynamics shows that, Pμ-a.s., if ξ ∈ X2 satisfies ξt(i) = ξt(i + 1) = ξt(i + 2) = 0 for some , then also ξt−1(i) = ξt−1(i + 1) = ξt−1(i + 2) = 0. It follows that ξs(i) = ξs(i + 1) = ξs(i + 2) = 0 for all s ≤ t and, by the invariance of Pμ under time translations, for all s. The conclusion follows from Lemma 2.5.
Suppose that the conclusion is false. By translation invariance, we may assume that for some (necessarily odd) positive integer j, μ(Aj) > 0, where Aj = {η∣hη(j) = 3}. We take j to be the minimal value for which this holds. By (a), j > 3, and minimality of j implies that if η ∈ Aj, then a.s. η(1:j) = 00(10)(j−3)/20. Now, by Lemma 2.5 [as in (a)], Pμ(B) > 0, where B = {ξ ∈ X2∣ξ0 ∈ Aj, ξ−1 ∉ Aj}. On the other hand, if ξ ∈ B, then elementary analysis shows that, Pμ-a.s., some translate of ξ−1 belongs to Aj′ for some j′ < j [for example, if j = 9, then ξ−1(1:j) must be one of 1100(10)20, 00(10)2011, 110 010 011, or 000 111 000]. This contradicts the minimality of j.■
III. LOW DENSITY
In this section, we describe all TIS states of low density (ρ < 1/2 for the F-SSEP, for the SSM). We first show that all ETIS states for the F-SSEP are frozen.
Let have density ρ < 1/2. Then, μ(F) = 1.
To describe all low-density states, we introduce , the set of ETI states supported on F, and . Since , , and thus, is indeed a λ-family (see Definition 2.3), with indexing map the identity. One checks easily that so that is also a λ-family, with indexing map Ψlow = Φϕ. Note that has density 1 and has density 1/2, but that otherwise the states in and have densities less than 1 or less than 1/2, respectively.
(a) The set of ETIS states for the F-SSEP with density ρ < 1/2 is , and (b) the set of ETIS states for the SSM with density is .
For (a), note that the inclusion is trivial, while conversely every state in with density less than 1/2 belongs to by Lemma 3.1. By virtue of Theorem 2.1, (b) is an immediate consequence of (a).■
Finally, we ask the following question: If the F-SSEP is started in an initial state μ0, which is a Bernoulli measure with density ρ < 1/2, what is the final distribution of frozen configurations? As discussed in Remark 1.1, in earlier work, we answered this question for several other facilitated exclusion processes, finding a common limiting distribution . For the current model, the limit is different (see below), but beyond that we have only a partial description.
Let μt = μt−1Q, t = 1, 2, …, be the state at time t, with μ0 as above, and for η ∈ X, let .
The limiting measure μ∞ = limt→∞μt exists and satisfies μ∞({0 ∈ Sη}) > 0. Under the conditional measure μ∞(·∣0 ∈ Sη), S is a renewal process.
Next, we show that q > 0. Let At be the event that for all L ≥ 1, there are in the configuration ξt at most L/2 particles on sites 1, 2, …, L. A standard gambler’s ruin computation18 shows that μ0(A0) = (1 − 2ρ)/(1 − ρ). Now, when At holds, no particle can cross the bond ⟨0, 1⟩ at the next time step from the L = 1 condition. Moreover, At ⊂ At+1. Thus, q ≥ μ0(A0) > 0.
To establish the existence of μ∞, and, in fact, a stronger result, the -almost sure existence of η∞ ≔ limt→∞ξt, one shows from that for any L > 0, . For ξ ∈ B−k ∩ Bl, simple considerations of the system in a finite region then imply that exists, -a.s. For more details, see the Proof of Lemma 3.6 of Ref. 10.
Since μ∞ is the distribution of η∞ under , we must show that is a renewal process under the conditional measure . Now, from (3.2), we have that iff ξ ∈ Bi, and if we condition on , that is, on B0, then what happens to the left of site −2 is independent of what happens to the right of site 0. Thus, if, under this conditioning, we label the points of sequentially as , with s0 = 0, so that ξt(sk − 2:sk) = 000 for all t and k, the differences sk − sk−1 are independent.■
Let us condition on and adopt the notation of the previous proof. Then, either s1 = 1, an event with (conditional) probability 1 − ρ, or s1 ≥ 4; in the latter case, η∞(−2:s1) = 000 σ 000, with σ being any string that begins and ends with 1 and contains no substrings 11 or 000. To complete the description of μ∞, one would need to find the distribution of these σ (and hence of s1 − s0); we have only partial results in this direction. However, one finds easily that, for example, μ∞(η(1:6) = 01101∣0 ∈ Sη) = ρ2(1 − ρ)4; on the other hand, with as introduced in Remark 1.1, ,10–12 establishing the difference of μ∞ and .
IV. DENSITIES ρ = 1/2 AND
In this section, we describe all ETIS states of density 1/2 for the F-SSEP or density 1 for the SSM. We first show that for such a state in the F-SSEP, the height profile hη [see (2.1)] is a.s. confined to a strip of height at most two. For η ∈ X, we let Δ(η) = supi<j|hη(j) − hη(i)|.
If has density ρ = 1/2, then, μ-a.s., Δ(η) ≤ 2.
By Lemma 2.4, we may assume that either μ(F) = 0 or μ(F) = 1. Now, μ(1) is the only TI state of density 1/2 supported on F, and it satisfies the conclusion of the lemma. Consider then the case μ(F) = 0. By Lemma 2.6(b), hη(j) − hη(i) ≤ 2 for i < j, so by translation invariance, it suffices to show that for any j > 0, hη(j) ≥ −2 μ-a.s.; moreover, it suffices to verify the result for each ergodic component of μ.
Suppose then that μ is ergodic but that for some j > 0, which we take to be minimal, . Then, from Lemma 2.6(b) and the minimality of j, also , and with ergodicity, this implies that, μ-a.s., hη has a negative overall slope. However, this is inconsistent with μ having density 1/2.■
We can now classify the states in with density 1/2. Consider a general η with Δ(η) ≤ 2; a portion of a typical height profile [with Δ(η) = 2] is shown in Fig. 1. As indicated there, we may partition η into left-moving (L), right-moving (R), and transition (T) regions, where T denotes a maximal region in which pairs of 0’s alternate with pairs of 1’s, L a region between two T regions having the form (10)k for some k ≥ 1, and R a region between two T regions having the form (01)k, k ≥ 1.
The naming of these regions reflects the fact that a configuration in which only L and T (respectively, R and T) regions appear translates to the left (respectively, right) at velocity 2 under the dynamics: if ηt is such a configuration, then ηt+1 = τ−2ηt (respectively, ηt+1 = τ2η). We will see below that all TIS states are supported on such configurations. The two simplest examples of such states, μ(1) and μ(2), were defined in (2.2); μ(1) may be viewed as supported on configurations with a single L, or equivalently a single R, region, and μ(2) is supported on configurations consisting of a single T region.
It is straightforward to work out further rules for the evolution of the configurations with Δ(η) ≤ 2. Such configurations cannot contain the pattern 11 011, and hence, the evolution is deterministic. Boundaries between regions usually move with velocity 2, L|T and T|L boundaries move to the left and R|T and T|R boundaries move to the right. However, if R and L regions are separated by a T region that is a single pair of 0’s, R|00|L, then both boundaries are stationary. If in the resulting T|R|00|L|T situation the L region is shorter than the R region, then the (left-moving) L|T boundary will eventually reach the 00|L boundary, at which time the L region will disappear and the 00 and T regions amalgamate into a single T region; the situation is similar when the R region is shorter or the two regions are the same length.
Following these ideas, one easily sees that, on a ring, any initial configuration evolves to one in which either no L region or no R region occurs. No such conclusion is possible when the ring is replaced by , but similar considerations do imply the following: For any configuration η with Δ(η) ≤ 2, the minimum size δ = δ(η) of a maximal uniform block—a maximal right block, a region of the form T|R|T|⋯|T|R|T preceded and followed by L regions, or a maximal left block, defined in a parallel way—must increase if δ < ∞, within a time proportional to δ. From this, it follows that any TI stationary state for ρ = 1/2 must be supported on configurations with δ = ∞, i.e., on configurations consisting of a single maximal uniform block or of a maximal right block adjacent to a maximal left block. However, the set of configurations of the latter sort must have probability 0 in any TI state.
Rather than filling in the straightforward details of the argument just sketched, we now give a different and shorter (though perhaps less intuitive) argument. Let Xleft (respectively, Xright) denote the set of configurations η ∈ X with Δ(η) = 2, which contain no R (respectively, no L) region. By convention, we suppose that Xleft and Xright contain η(1) and τη(1) (see Sec. II); then, Xleft ∩ Xright consists of η(1), η(2), and their translates. Recall also the spaces Xρ, , , and , defined in Sec. I.
When ρ = 1/2, .
When , .
Before giving the proof, we explain how the ETIS states of the theorem are organized into the λ-families of Definition 2.3. Consider first ; here, and are λ-families that we denote, respectively, and . The substitution map given by 1 → 20, 0 → 1 gives rise to an indexing bijection , and similarly, we obtain from ϕright, the substitution map sending 1 → 02, 0 → 1. The indexing maps for and are and or can be obtained directly from the substitution maps 1 → 1100, 0 → 10 and 1 → 0011, 0 → 01, respectively. Note that and .
Since the F-SSEP dynamics on Xleft or Xright is simply left or right translation, respectively, clearly . Suppose conversely that . Since μ is an ETIS state and Xleft and Xright are invariant under the dynamics, it suffices to prove that μ(Xleft ∪ Xright) = 1, i.e., that the set of configurations η that have Δ(η) = 2, and contain both L and T regions, has measure zero.
We first show that, μ-a.s., no configuration contains the string 010010 (corresponding to regions R|T|L with T having just two sites). Let E be the event that sites 1 and 2 both belong to an R region and that η(1:2) = 01. Then, from the dynamical rules,However, , since the density of left and right ends of R regions must be the same, so that, with the stationarity of μ, (4.1) implies that , as claimed.(4.1)Now, if μ(Xleft ∪ Xright) < 1, then there is a minimal k such that . From the claim above, k > 0. However, if ξt(1:4k + 6) = 0100(1100)k10, then ξt+1(3:4k + 4) = 0100(1100)k−110, contradicting the minimality of k.
- (b)
By (a) and Theorem 2.1 (using and ), we have
V. HIGH DENSITY
Most of our discussion of the high density region, ρ > 1/2 for the F-SSEP or for the SSM, will be carried out for the SSM. We first obtain a reduction of the configuration space of the model to the space , the set of configurations for which no two adjacent sites both have short stacks (see Sec. I). Note that any extremal TI state in must have density satisfying . For future reference, we also note that is the set of F-SSEP configurations that do not contain any of the substrings 000, 0100, 0010, and 01 010.
Every TIS state for the stack dynamics with density is supported on ; equivalently, every TIS state for the F-SSEP dynamics with density ρ > 1/2 is supported on H.
It is convenient to work primarily in the stack model. We observe first that since 00 in the stack model corresponds to 000 in the F-SSEP model, Lemma 2.6 implies that every with density assigns zero probability to the set of all configurations containing the substring 00.
Now, we suppose that has density and is such that configurations containing the string 10 occur with nonzero probability under , and derive a contradiction; we may assume that is ergodic. For , let be the event that satisfies mt(i:i + 1) = 10; then, for m ∈ Et,i, we know from Lemma 2.5 that there must a.s. exist times t0 and t1, with t0 ≤ t < t1, such that m ∈ Es,i for t0 ≤ s < t1 but and . Then, elementary consideration of the dynamics, using the fact the 00 does not occur, shows that necessarily , i.e., the 10 string cannot be “created” at sites (i, i + 1) but rather “moves” there from sites (i − 1, i). However, such a string cannot vanish, since is stationary and, hence, the density of 10 strings is constant in time, and again simple considerations show that necessarily and . The conclusion is that, -a.s., 10 substrings persist throughout time, moving to the right in the sense that there exist times t0 < t1 < t2 < ⋯ such that mt(i + k:i + k + 1) = 10 for tk ≤ t < tk+1.
A similar analysis applies to 01 strings, except that these move to the left. However, we claim that cannot give positive density to both 10 and 01 strings. For if it did, both would occur with positive frequency in the same configuration, by the ergodicity of , and would then “collide”, that is, the configuration 101 would occur with positive frequency (1001 is ruled out because 00 is) and then neither could continue to move without the destruction of the other, a contradiction. Thus, we may assume, without loss of generality, that supports a positive density of 10 substrings but that, -a.s., 01 strings do not occur.
Now let k be the minimal positive integer such that , where ; such a k exists because , and we have assumed that . From the fact that 00 and 01 do not occur, it follows that if nt ∈ Ak, then nt(1:k) has one of two forms: (i) nt(1: k) = 102(02)p1qx, with x ≥ 2, or (ii) nt(1:k) = 10(20)py, with y ≥ 3; here, p and q are non-negative integers. We show that each of these cases leads to a contradiction.
If (i) holds, then one checks, by considering various special cases, that with probability at least 1/2 either (i.a) neither nt+1(1:2) = 10 nor nt+1(2 : 3) = 10, contradicting the possible evolution of a 10 pair as discussed above or (i.b) τ−1nt+1 lies in case (i) of Ak−2, contradicting the minimality of k. For example, if p = q = 0 so that k = 4 and nt(1:4) = 102x, then nt(2 : 3) = 12 with probability 1/2 [case 1.a)], while if q ≥ 2 , then nt+1(2:k − 2) = 102(02)p1q−22 so that τ−1nt+1 ∈ Ak−2 [case (1.b)].
Suppose then that (ii) holds. If p = 0 then, as in case (i.a), the 10 disappears, and if p ≥ 1 and y ≥ 4, then τ−1nt+1 ∈ Ak−1; each of these outcomes contradicts our assumptions. If p ≥ 1 and y = 3, then we must consider an additional site and so write nt(k + 1) = z. If z ≥ 2, then, with probability 1/2, nt+1(2:k) = 102(02)p−13 and so τ−1nt+1 ∈ Ak−1. Finally, if z = 1 or z = 0, then nt+1(2:k) = 102(02)p−11z′ with z′ ≥ 2, so that τ−1nt+1 lies in Ak but falls under case (i), and this is a contradiction by the analysis of the previous paragraph. For this last step, we need to observe that if z = 0, then necessarily nt(k + 2) ≥ 2, since neither 00 nor 01 can occur in nt.
To complete the proof, we must show that, -a.s., the string 11 cannot occur in n. However, as for the initial analysis of 10 above, if satisfies mt(i:i + 1) = 11, then, -a.s., there must be a time t0 ≤ t with but , and it is easy to see by considering various possible values of that this cannot happen.■
In the remainder of Sec. V, we study the ETIS states of the SSM considered as a process with state space . Theorem 5.1 justifies this choice for states with density . Moreover, the state introduced in Sec. I was shown in Sec. IV to be an ETIS state of density for the SSM; is supported on (and is the only such state). It is convenient to include this state in our study so that from now on, we assume that .
The dynamical rules of the SSM simplify on as follows: if nt(i) is 0 or 1, then in the transition to nt+1, a particle moves from each of the sites i + 1 and i − 1 to i, while if n(j), n(j + 1) ≥2, a particle moves from j to j + 1 or the reverse, each with probability 1/2. Since at each time step a particle must move across each bond, the parity (−1)n(i) of the stack height at each site i is conserved. Let be the space of parity sequences, define the parity map by (n) (i) = (1 − (−1)n(i))/2, and for σ ∈ S, define the parity sector by so that iff, for all i, n(i) and σ(i) have the same parity.
Since for each σ ∈ S the parity sector is invariant under the dynamics, we obtain by restriction a dynamical system on each . In Sec. V A, we discuss the stationary states in the even sector , where e is the parity sequence satisfying e(i) = 0 for all i, and in Sec. V B and Appendix B, we show how these give rise to all the ETIS states on .
A. ETIS states in the even sector
Our next result describes a family of ETIS states for the SSM in the even sector; the proof will be given shortly.
As we will see in Sec. V B and Appendix B, for a full discussion of the ETIS states of the SSM on , we need to know all stationary states on , both TI and non-TI (should any of the latter exist). We have the following conjecture:
For each , is the unique stationary state of the SSM on with density .
In Sec. V B, we will discuss the ETIS states on under the assumption that Conjecture 5.3 holds, and in Appendix B, we turn to the general case.
We begin our discussion of Theorem 5.2 with the consideration of the SSM on a ring of 2L + 1 sites, indexed by IL ≔ { − L, …, L}; the configuration space is the set of elements for which n(i) is even for all i and for which no two adjacent sites both have height zero. For the moment, we take a fixed number N of particles, with N even and N ≥ 2L + 2, with the corresponding configuration space . For , let z(n) be the number of sites i with n(i) = 0. In a transition from nt to nt+1, the direction of particle movement across 2z(nt) bonds is determined and across the remainder is chosen randomly; moreover, a given transition can occur via at most one set of these choices unless nt = nt+1, in which case there are two possibilities [this occurs iff z(nt) = 0]. Thus, the probability P(nt, nt+1) of such a transition, if nonzero, is . Then, a TIS state μ(N,L) is given by , with a normalizing constant, since because P(n, n′) = 0 iff P(n′, n) = 0, μ(N,L) satisfies the detailed balance condition μ(N,L)(n)P(n′, n) = μ(N,L) (n′)P(n, n′). It is straightforward to check that the dynamics permits transition from any configuration in to any other so that μ(N,L) is the unique TIS state.
The state μ(N,L) is a Gibbs measure arising from the one-particle potential V(n) of (5.1), that is, . (One may also view μ(N,L) as a Gibbs measure on the space of all N-particle configurations, with one- and two-body hard core potentials, that is, formal potentials taking infinite values, that impose the restrictions of .) In order to pass to the L → ∞, limit it is convenient to consider the grand canonical measure with fugacity ζ ≥ 0,
with again a normalizing constant.
The limiting measure μ(ζ,∞) = limL→∞μ(ζ,L) exists for 0 ≤ ζ < 1 and is a TIS state of density 1/(1 − ζ) for the SSM on . Moreover, μ(0,∞) = μ(2) and μ(ζ,∞) is mixing if ζ > 1.
The case ζ = 0 follows immediately from the fact, evident from (5.2), that μ(0,L) gives equal weight to the 2L + 1 configurations in with ∑in(i) = 2L + 2. From now on, we assume that 0 < ζ < 1.
The theorem follows immediately from Lemma 5.4 via .■
There is an alternative way to describe the state μ(ζ,∞) (and hence also ). Consider the image of μ(ζ,∞) under the map defined by F(n)(j) = min{1, n(j)}, which effectively classes sites simply as occupied or empty. The image measure is again Gibbsian, with no interactions other than the exclusion of configurations containing adjacent holes, so that it is, after an interchange of the roles of particles and holes, the equilibrium state of the familiar nearest-neighbor hard core model. The holes in this system have effective fugacity (1 − ζ2)/(2ζ)2 (relative to a fugacity of 1 for the particles), and from (5.7), the density of holes is (1 − ζ)/2. The full state μ(ζ,∞) is then obtained by first conditioning F(n) = η for some η ∈ {0,1}∞ with no adjacent holes, distributed according to F*μ(ζ,∞), and then distributing particles on each site j for which η(j) = 1 independently, with distribution μ{n(j) = 2i} = ζ2i−1/(1 − ζ2), i = 1, 2, ….
B. ETIS states for the SSM
We now discuss the passage from stationary states of the SSM on the even sector to general high-density ETIS states, specifically, to states with as well as the special state μ(2) with . By Theorem 5.1, these are precisely the ETIS states on . Let us define by γ(m, σ) = m + σ [with component-wise addition: (m + σ)(i) ≔ m(i) + σ(i)]. Note that for fixed σ ∈ S, γ(·, σ) is a bijection of with . We define the dynamics in to be constant on S.
A measure μ on is an ETIS state for the SSM iff is an ETIS state on .
Each ETIS state of density on has the form , where λ is an ergodic TI probability measure on S and μσ, σ ∈ S, are stationary probability measures on satisfying μτσ = τ*μσ. Moreover, if λ has density κ, then λ-almost all μσ have density .
The map γ clearly commutes with translations and with the dynamics. Thus, γ* and carry TIS states to TIS states, and they clearly preserve extremality.
The form is immediate, with λ being the probability measure on S giving the distribution of σ and μσ being the conditional probability measure on , given σ. The stationarity of implies the stationarity of each μσ, and the translation invariance of yields the translation invariance of λ and the relation μτσ = τ*μσ. λ must be ergodic, since a decomposition of λ as a convex combination of TI measures would yield immediately a decomposition of μ in terms of TIS measures. Finally, since -a.s. configurations have density , λ-a.s. each μσ must have density .■
Throughout the remainder of this section, we assume that Conjecture 5.3 holds. See Appendix B for an analysis of the situation when this assumption is not valid.
Suppose that of Theorem 5.2 are the only stationary states of the SSM on , i.e., that Conjecture 5.3 holds. Then, the ETIS states with density are precisely the states , with λ being an ergodic TI probability measure on S of density and .
Before giving the proof, we note an immediate consequence of this result and Theorem 2.1.
Under the hypotheses of Theorem 5.7, the ETIS states of the F-SSEP with density ρ > 1/2 are the states ; has density .
By Lemma 5.6, it suffices to prove that the ETIS states on are the states described in the theorem. The latter are clearly TIS. If is an ETIS state on of density , then Lemma 5.6 and Conjecture 5.3 imply that . Conversely, a decomposition of a state as described in the theorem into extremal components must, by this and the ergodicity of λ, be trivial.■
The states of the SSM with are defined in Theorem 5.7; it is natural then to define also , with the point mass on the zero configuration e.
It follows from the theorem that, whenever is defined, the density κ of the measure λ satisfies . The case , corresponding, in the notation of the theorem, to , is of particular interest; see (c) and (d).
is extremal in the class of TIS states, but it may not be ergodic under translations. For example, if σ ∈ S has even period p and density κ, and λ is the superposition of the point masses on σ and its translates, then if (i.e., if ), is a superposition of two ergodic measures, these being the superpositions of the translates of n* + σ and τn* + σ, respectively. When, in general, can such non-ergodicity occur? First, if , then , as the product of a mixing and an ergodic measure, is ergodic, and hence so is . On the other hand, if , we use the fact that will be ergodic iff the eigenvalue 1 of the translation operator in is simple; since the translation on has simple eigenvalues of ±1 and no others, we conclude that is ergodic iff the translation operator on L2(S, λ) does not have the eigenvalue −1.
If λ has density κ, then, μ(1+κ,λ)-a.s., each configuration n has sites with 0 or 1 particle(s) alternating with sites with 2 or 3 particles, and the dynamics carries such a configuration to the one obtained from it by the substitutions 0 → 2, 1 → 3, 2 → 0, and 3 → 1. The evolution of these configurations is thus periodic, of period 2.
We finally observe that the states for fixed (where as usual κ is the density of λ) form a λ-family (see Definition 2.3), which we denote . The indexing map is given by , where we have made the identification . From Corollary 5.8, then, the ETIS states of the F-SSEP with density ρ > 1/2, together with the state μ(2), form the λ-families .
VI. SUMMARY
The results of this paper are summarized, under the assumption that Conjecture 5.3 holds, by Fig. 2, which gives a symbolic depiction of the relations among the λ-families of regular ETIS states of the SSM. The heavy black lines denote λ-families. and have been separated for visibility, but, in fact, both lie at . The state belongs to all three of the families , , and , and the state belongs to , , and [see Remark 5.9(a)]. κ denotes the density of a measure ; this variable is relevant only for the state (for which κ = 0) and for states with . The shaded region is filled with the λ-families ; the family for and three other representative families are shown.
DEDICATION
This paper is dedicated to the memory of Freeman Dyson, friend and teacher.
ACKNOWLEDGMENTS
The work of J.L.L. was supported, in part, by the AFOSR. J.L.L. thanks the IAS for its hospitality.
AUTHOR DECLARATIONS
Conflict of Interest
The authors have no conflicts to disclose.
DATA AVAILABILITY
Data sharing is not applicable to this article as no new data were created or analyzed in this study.
APPENDIX A: EQUIVALENCE OF TI MEASURES UNDER SUBSTITUTIONS
In this appendix, we give a construction that will be used at several points in this paper. Suppose that and are countable alphabets, that and with typical elements and η ∈ Y, and that for each , we specify a finite sequence χ(s) = ts(1)…ts(k(s)) of elements of [that is, a word of k(s) letters in the alphabet ]. Then, we define to be the map that substitutes χ(s) for s, that is,
with χ(ζ(1)) beginning at site 1, so that ϕ(ζ)(1) = tζ(1)(1). For , we define and ; for 0 ≤ j ≤ k(s) − 1, we set Ysj = τ−jYs and define by . From now on, we assume that the χ(s) are such that the sets Ysj are pairwise disjoint.
We call a TI measure on regular if is finite, i.e., if , and a TI measure ν on Y regular if it is supported on , the smallest translation invariant subset of containing . Let denote the space of regular TI states on and denote the space of regular TI states on Y. If and , define and .
This is straightforward to check. The final statement follows from the fact that if and only if , where and .■
We now suppose that we are given dynamical rules in the spaces and Y, that is, translation invariant Markov processes with state spaces and Y, specified by respective TI transition kernels and Q(η, B). We will say that or Q preserves ergodicity if (respectively, νQ) is ergodic whenever (respectively, ν) is; preserving regularity is defined similarly.
We next want to give a condition which will imply that the mapping Φ preserves these dynamics, i.e., that ; we will need some further notation. Let be the set of pairs (ζ, η) such that η is a (possibly trivial) translate of ϕ(ζ), and let and π be the projections of onto the first and second components, respectively, of .
To show that there is a τ-coupling of Q and , it suffices to find a restricted transition probability , which satisfies (A3) and (A4) when η = ϕ(ζ). can then be extended to the rest of by setting when η = τqϕ(ζ), choosing q, when periodicity of ϕ(ζ) necessitates a choice, to be the minimal non-negative q with η = τqϕ(ζ). Here, acts on via .
Suppose that Q and are TI Markov transition kernels on and Y, respectively, which preserve ergodicity and regularity and for which there exists a τ-coupling . Then, for any TI state and any n ≥ 1, .
If Q and are as in Theorem A.4, then Φ is a bijection of with , i.e., is stationary for if and only if is stationary for Q.
The corollary is, of course, immediate. The idea of the Proof of Theorem A.4 is taken from Refs. 10 and 12:
It suffices to verify the result for ergodic. Then, since and Q preserve ergodicity, as does Φ, and are ergodic, so that these two measures are either equal or mutually singular. Hence, to prove their equality, it suffices to find a nonzero measure λ with and .
Let be a τ-coupling of and Q with state space , as in Definition A.2, define by ψ(ζ) ≔ (ζ, ϕ(ζ)), and for , let , so that and . Fix n ≥ 1, and let be such that , where , and define , , and . We claim that (i) and that, for an appropriate constant c > 0, (ii) and (iii) . Since is TI, the proof is completed by taking λ = cν′.
In the remainder of this appendix, we discuss the applications we make of these results. Theorem A.1 is used in Sec. IV; the substitution maps there are denoted ϕleft and ϕright. Theorems A.1 and A.4 are used to obtain a correspondence between the stationary states of the Symmetric Stack Model (SSM) and of the Facilitated Simple Symmetric Exclusion Process (F-SSEP), a correspondence first introduced in Sec. I (see that section and Sec. II for the definition of the transition kernels and Q for these models) and used throughout this paper. In this application, , , and for , χ(n) ≔ 01n; we write and but keep the notation for the substitution map obtained from χ. The general definition of regularity of measures given above corresponds in this case to the definition given in Sec. II, and it is clear that and Q preserve regularity.
and Q preserve ergodicity.
We consider (the proof for Q is similar), and so we must show that if , then is ergodic. We define the probability space (Ω, P) by , , where κ is the Bernoulli measure with parameter 1/2, and write a typical element of Ω as (n, α). Then, we can introduce a concrete realization on Ω of one step of the process, from n0 distributed as to n1 distributed as , as follows. Recall that if n0 has a short stack on either i or i + 1, then the movement, or non-movement, of a particle across the bond ⟨i, i + 1⟩, in passing from n0 to n1, is determined by the rule given in Sec. I; we supplement this rule by requiring that if n0 has tall stacks at both i and i + 1, then a particle moves from site i to site i + 1 if α(i) = 1 and from i + 1 to i if α(i) = 0.
As the product of measures that are, respectively, ergodic and mixing under translations, P is ergodic under translations. It follows that is the covariant image of an ergodic measure and hence is ergodic.■
There exists a τ-coupling of the Markov transitions kernels and Q for the SSM and F-SSEP.
For the dynamics under , we allow n0 to evolve to n1 according to the dynamics, and let n1 and η0 determine η1 as follows. Write . Then, if in passing from n0 to n1 a particle jumps from site i − 1 to site i, then in passing from η0 to η1 a particle jumps from site K(i) − 1 to site K(i), while if a particle jumps from site i to site i − 1 in passing from n0 to n1, then one jumps from site K(i) + 1 to site K(i) in passing from η0 to η1. It is straightforward to verify that then and with η1 distributed according to Q(η0, ·).■
With Lemma A.6 and Theorem A.7, we can apply Corollary A.5 to obtain the correspondence of the F-SSEP and SSM stationary states. The result is summarized in Theorem 2.1.
APPENDIX B: POSSIBLE ETIS STATES OF THE SSM FOR
In this appendix, we discuss, in the case where Conjecture 5.3 is not satisfied, the passage from stationary states of the SSM on the even sector to general ETIS states of the SSM with density . By Theorem 5.1, the latter all have support on ; moreover, as observed in Sec. V, the stationary states on include in addition only . Let denote the family of stationary states on with density , that is, states ν for which ν-almost every satisfies
Let be the extremal elements of . We completely analyze the structure of ETIS states on , in terms of the states of , in two cases: when for each , contains only TI states (Theorem B.1), and when for each , is countable (Theorem B.5). The first case is quite simple.
If all stationary states on are translation invariant, then every ETIS state μ on of density is of the form γ*(μ* × λ), with λ being an ergodic TI measure on S of density κ and , where . Conversely, every state of this form is ETIS.
If μ is an ETIS state on of density , then Lemma 5.6 implies that with and μτσ = τ*μσ. However, if all stationary states on are TI, then μσ = μτσ for all σ so that the ergodicity of λ implies that μσ is independent of σ, λ-a.s., and extremality of μ implies that this state, μ*, must be ETIS on . The converse is clear.■
We now consider the possibility of non-TI stationary states on . In the next definition, we introduce a class of stationary states on , which we call basic states, and a further restriction of this class to irreducible basic states.
Let λ be an ergodic TI measure on S, let have period n = n(ν) under translation, and let m and q be positive integers such that n = qm.
A (λ, m)-partition of S is an ordered family of subsets of S such that ⋃iAi = S and Ai ∩ Aj = ∅ for 0 ≤ i < j ≤ m − 1, both up to sets of λ-measure zero, and such that the family is cyclically permuted by translation: τ(Ak) = A(k+1) mod m. Translations act on such partitions via (τA)k = A(k+1) mod m.
- Let A be a (λ, m)-partition of S, and let . Then, is the state on with , where iff σ ∈ Ak, i.e.,and will be called basic states.(B2)
The basic state is reduced by the basic state if A′ is a proper refinement of A; is then called reducible, and we say also that is reducible. If and are not reducible, then they are irreducible.
Observe that whether or not is reducible depends only on λ, A, and n, the period of the orbit of ν under the action of τ*: is reducible precisely when there is a (λ, m′)-partition A′ of S such that m′ divides n and A′ is a proper refinement of A. Equivalently, is irreducible when the action of τn on A0, equipped with the invariant measure , is ergodic.
We next give some simple consequences of Definition B.2.
Let be a basic state. Then, we have the following:
is stationary.
.
For any σ ∈ S, . In particular, is TI. Moreover, if λ has density κ, then has density .
If the basic state reduces , and , then for i = 0, … , m − 1, where m = |A| and p = |A′|/|A|. Moreover, .
- If is irreducible, then it cannot be written as a convex combination of other ; more generally, we cannot havewith α being a probability measure on triples β = (λ′, ν′, A′), which assigns zero probability to (λ, ν, A).(B3)
(a), (b), and (c) are immediate.
(d) The first statement follows from . For the second, it suffices to prove that for all σ, and this follows from the first and (B2), by straightforward rearrangement of sums.
If is countable for each , then each ETIS state on is an irreducible basic state.
We write , with either or a finite set {1, 2, …, J}, and allow the translation operator τ to act on via ντj = τ*νj. Let denote the set of orbits in under translation.
Now let μ be an ETIS state on of density . Then, from Lemma 5.6, we know that with , λ being ergodic, μσ being stationary, and μτσ = τ*μσ. For each σ ∈ S, we have , with coefficients aσ,j that, from translation invariance, satisfy aτσ,τj = aσ,j. Now note that if , then is TI and, hence, constant λ-a.s.; from now on, we write this as Z(c). Define by and by , so that ; since the are TIS, the extremality of implies that for some .
Now, we can give the second main result of this appendix.
If is countable for each , then the ETIS states on are precisely the basic irreducible states.
Lemma B.4 tells us that every ETIS state is an irreducible basic state. It follows from this that the decomposition of any irreducible basic state into ETIS components must be of the form (B3) and hence, by Lemma B.3 (e), that such a state must be ETIS.■