A recently proposed approach for avoiding the ultraviolet divergence of Hamiltonians with particle creation is based on interior-boundary conditions (IBCs). The approach works well in the non-relativistic case, i.e., for the Laplacian operator. Here, we study how the approach can be applied to Dirac operators. While this has successfully been done already in one space dimension, and more generally for codimension-1 boundaries, the situation of point sources in three dimensions corresponds to a codimension-3 boundary. One would expect that, for such a boundary, Dirac operators do not allow for boundary conditions because they are known not to allow for point interactions in 3D, which also correspond to a boundary condition. Indeed, we confirm this expectation here by proving that there is no self-adjoint operator on a (truncated) Fock space that would correspond to a Dirac operator with an IBC at configurations with a particle at the origin. However, we also present a positive result showing that there are self-adjoint operators with an IBC (on the boundary consisting of configurations with a particle at the origin) that are away from those configurations, given by a Dirac operator plus a sufficiently strong Coulomb potential.
I. INTRODUCTION
Hamiltonians for quantum theories with particle creation and annihilation are often plagued by ultraviolet divergence.1–3 For defining such a Hamiltonian in a rigorous way, one might employ an ultraviolet cutoff corresponding to smearing out the source of particle creation over a positive volume, or in some cases, one can obtain a renormalized Hamiltonian by taking a limit of the cutoff Hamiltonian in which the volume of the source tends to zero.4–7 Another more recent approach is based on interior-boundary conditions (IBCs)8,9 and yields directly (i.e., without taking a limit) a Hamiltonian suitable for a point source. Here, the wave function ψ is a function on the configuration space
of a variable number of particles that can move in the one-particle space , for example
if particles can be created at a point source fixed at the origin . In this example, the boundary of consists of configurations with at least one particle at the origin,
The IBC is a condition on ψ relating values on the boundary and values in the interior, more precisely, relating the values on two configurations q, q′ that differ by the creation (respectively, annihilation) of a particle at the origin,
and
As shown by Lampart et al.,10 a Hamiltonian with particle creation at the origin can be defined rigorously in this way in the non-relativistic case without UV divergence or the need for renormalization. Our goal here is to examine in what way and to what extent this approach can be extended to the Dirac equation.
There are already two works about IBCs for the Dirac equation: Schmidt et al.11 explored what IBCs for the Dirac equation can look like on a codimension-1 boundary. However, in our case, boundary (3) has codimension 3. Lienert and Nickel12 developed a quantum field theory (QFT) model in one space dimension using Dirac particles and an IBC that allows two particles to merge into one or one particle to split in two. In contrast, we consider here space dimension 3.
We present here a negative result and a positive one. The negative result (Theorem 1) asserts, roughly speaking, that in three space dimensions, there exists no self-adjoint Hamiltonian for the configuration space as in (1)–(3) (or even the truncated one allowing only N = 0 and N = 1) that acts like the free Dirac Hamiltonian away from the boundary but involves particle creation. Put differently, the free Dirac equation cannot be combined with IBCs in three dimensions. The fact is analogous to the known impossibility of point interaction (δ potentials) for the Dirac equation in three dimensions (see, e.g., Refs. 13–15, Theorem 1.1), in particular, since the point interaction is described by a boundary condition,16,34 and for an external field that acts nontrivially only at , the relevant boundary for this boundary condition is precisely (3), or one sector thereof. Our proof of Theorem 1 makes use of the impossibility theorems for point interaction to deduce the impossibility of IBCs in this situation. We formulate some variants of Theorem 1 as Theorems 3 and 4.
The positive result (Theorem 6) concerns a way in which, nevertheless, a self-adjoint Hamiltonian with particle creation can be rigorously defined by means of an IBC and the Dirac equation for the configuration space as in (1)–(3); it is based on adding a potential. Specifically, we show in Theorem 6 that if a Coulomb potential of sufficient strength, centered at the origin and acting on each of the particles in the model, is added to the action of the Hamiltonian away from the boundary, then a self-adjoint version of the Hamiltonian exists that involves an IBC and leads to particle creation and annihilation at the origin, analogously to the non-relativistic case with the Laplacian operator. The IBC is analogous to the known IBCs for codimension-1 boundaries.11 We formulate the result for a truncated Fock space with only the N = 0 and N = 1 sectors.
The results are formulated in detail in Sec. II. They can be expressed as statements about self-adjoint extensions. That is because, when considering a truncated Fock space (N ≤ Nmax) and configuration space, for functions ψ that vanish in a neighborhood of the boundary in the top sector Nmax and also vanish in all lower sectors, we know how the desired Hamiltonian should act: in the same way as the Dirac operator Hfree of Nmax particles (respectively, with a Coulomb potential). Let D° be the space of these functions (not dense). Thus, the desired Hamiltonian H is a self-adjoint extension of a (symmetric but not closed) operator H° = H|D° = Hfree|D°. (By the way, when we say “self-adjoint,” we always mean that the operator is densely defined.) The no-go result (Theorem 1) will show that H° has only one self-adjoint extension, viz., Hfree; that means that it is not possible to implement particle creation and annihilation at just one point 0, using IBCs or otherwise. Theorem 6 will take H° to include a suitable Coulomb potential and provide a self-adjoint extension (even several ones) featuring particle creation and annihilation. It remains to be seen whether and how IBCs can be employed in more realistic models of relativistic QFTs.
The IBC Hamiltonians provided by Theorem 6 are neither translation invariant nor rotation invariant, but that was only to be expected: the model cannot be translation invariant, given that the source is fixed at the origin, and the emission of a spin- particle by a spinless source cannot conserve angular momentum and, thus, cannot be rotation invariant. (An alternative proof is given in Sec. II D.)17
Here are further comments on the literature. Some forms of interior-boundary conditions were considered, not necessarily with the UV problem in mind, early on by Moshinsky.18–20 Self-adjoint Hamiltonians based on IBCs and the Laplacian were first rigorously defined by Thomas21 and Yafaev.22 Lampart et al.10 extended these results to the full Fock space and showed that the non-relativistic IBC Hamiltonian agrees, up to addition of a constant, with the one obtained through UV cutoff and renormalization. Lampart and Schmidt23 further extended the proofs to moving sources in two space dimensions, and Lampart,24 in three dimensions. Keppeler and Sieber25 studied the one-dimensional non-relativistic case. Bohmian trajectories for IBC Hamiltonians were defined and studied in Refs. 26, 27 and 40. Other kinds of boundary conditions come up in the study of detection times (see Ref. 35). Further studies of IBC Hamiltonians and their properties include Refs. 28–33.
II. RESULTS
For comparison, it will be useful to recapitulate some aspects of the non-relativistic case in three dimensions with a single point source fixed at the origin.10 For simplicity, we consider a truncated Fock space of spinless particles,
with ⊕ the orthogonal sum of Hilbert spaces and S±⋯ the image of the symmetrization operator S+ or anti-symmetrization operator S− (subscript nr is for “non-relativistic case”). There is a five-parameter family of IBC Hamiltonians; some members of this family can be regarded as involving an external zero-range potential at the origin in addition to the particle source; there is a two-parameter subfamily that can be regarded as involving no such potential, i.e., as being a pure particle source. The remaining parameters are the energy E0 that must be expended for creating a particle and the strength g of particle creation. Let us fix values E0 > 0 and and call the corresponding operator Hnr. Hnr is a self-adjoint operator in ; let Dnr denote its domain of self-adjointness. Functions in Dnr satisfy the IBC
(suitably understood, and with r ↘ 0 meaning the limit from the right) for N = 0, …, Nmax − 1 and every unit vector . Another operator to compare to is the free Hamiltonian , which acts on functions ψ from its domain
(with H2 the second Sobolev space) according to
with H1nr,j the one-particle Hamiltonian
acting on particle j.
Now, we want to express that away from the boundary, Hnr acts like . However, the IBC enforces that if ψ(N) ≠ 0 for some N ≥ 0, then every higher sector, ψ(N′) with N′ > N, must be nonzero (and, in fact, unbounded) in a neighborhood of the boundary . In contrast, ψ can lie in Dnr if vanishes in a neighborhood of the boundary and ψ(N) = 0 for all N < Nmax; in fact, ψ will lie in Dnr if (where means smooth functions with compact support) and ψ(N) = 0 for all N < Nmax,
Note that since 0 was excluded from , “compact support” entails that the support stays away from the boundary. The symbol ⊕, when applied to sets that are not Hilbert spaces, should be understood as the Cartesian product, resulting in a subset of . On , Hnr acts like the free Hamiltonian,
That is both (Hnr, Dnr) and are self-adjoint extensions of . Note that is not a dense subspace of (whereas Dnr and are). The condition that (Hnr, Dnr) is an extension of expresses that in the highest sector, particle creation can occur only at the origin. In passing, we remark that Yafaev22 showed for Nmax = 1 that all self-adjoint extensions of belong to the five-parameter family of IBC Hamiltonians (which includes, as a subfamily, the Hamiltonians without particle creation but with point interaction at the origin).
A. No-go theorem
Now, we turn to the Dirac case. We define the truncated Fock space
(Although spin- particles are fermions in nature, we cover here also the mathematical case of Dirac particles that are bosons.) The one-particle Hamiltonian is the Dirac Hamiltonian
with mass m ≥ 0, which is self-adjoint on (first Sobolev space). Let be the free N-particle Hamiltonian, which acts according to
its domain of self-adjointness in , and
on the domain
Hfree is self-adjoint and is the (truncated) “second quantization” of H1 in .
The desired IBC Hamiltonian (H, D), or, in fact, any Hamiltonian that agrees with Hfree except for particle creation and annihilation at the origin, must be a self-adjoint extension of (H°, D°) with
and
Let .
Let Nmax > 0. For every self-adjoint extension (H, D) of (H°, D°), the highest sector decouples from the other sectors; that is, H is block diagonal with respect to the decomposition .
We give all proofs in Sec. III. To paraphrase the conclusion of Theorem 1, the time evolution generated by H involves no exchange between and the other sectors; no particle creation or annihilation occurs toward or from the Nmax-sector; in particular, is time independent. So, Theorem 1 implies that there is no IBC Hamiltonian for the Dirac equation in three space dimensions, as long as no further element such as potentials, space–time curvature, or other particles is introduced.
Theorem 1 is obtained by combining two theorems, Theorem 2 and Theorem 3. The former is a specialized form of a theorem of Svendsen.14
Let N ≥ 1 and the union of finitely many C∞ submanifolds of equal codimension c. Let H\M be the restriction of to . Then, H\M is essentially self-adjoint in if and only if c ≥ 2. In particular, the restriction of to is essentially self-adjoint, and its restriction to is essentially self-adjoint in .
The last sentence follows by taking
so c = 3 and . This theorem excludes point interaction for the free Dirac equation in three space dimensions. Note, however, that Theorem 1 is not a direct corollary of Theorem 2 because our Hilbert space is not but contains further sectors, and D° is not dense. What we need is the following statement, a kind of generalization of Theorem 1.
B. Hamiltonians with Coulomb potential
In this section and Sec. II C, we focus on the case of two sectors, i.e., Nmax = 1. Our positive result is about examples of Dirac Hamiltonians in 3D with particle creation by means of IBCs. These Hamiltonians are based on the one-particle Hamiltonian
which consists of the free Dirac Hamiltonian plus a Coulomb potential of strength q (i.e., q is the product of the charge at x and the charge at the origin). We will show in Theorem 6 that for , there exist IBC Hamiltonians. We conjecture that also for |q| ≥ 1, IBC Hamiltonians exist. On the other hand, the following theorem, a generalization of Theorem 1 in the case Nmax = 1, shows that for , no IBC Hamiltonian exists.
It is known (e.g., Ref. 36, Proposition A1) that for , (first Sobolev space), whereas for , the domain is bigger than the first Sobolev space. Theorem 4 follows by means of Theorem 3 from the following known theorem (Ref. 37, Theorem 6.9).38
In , the operator H1 as in (22) is essentially self-adjoint on if and only if .
C. Existence of IBC Hamiltonian
It will be helpful again to consider first the non-relativistic IBC Hamiltonian (Hnr, Dnr), now for Nmax = 1, so . We report a few facts:10 for every ψ ∈ Dnr, the upper sector is of the form
as x → 0, with (uniquely defined) “short distance coefficients” . ψ ∈ Dnr satisfies the IBC (6), which can be written in the form
and the Hamiltonian acts on ψ like
[At x = 0, Δψ(1), when understood in the distributional sense, includes a delta distribution stemming from the |x|−1 contribution in (28).]
Now, we turn again to the Dirac case with
and one-particle operator H1 as in (22). In the following, we take H1 to be an operator on the domain
with adjoint in .
The notation
is common for certain functions that form an orthonormal basis of (where means the unit sphere in ) and are simultaneous eigenvectors of J2, K, J3 with J = L + S the total angular momentum and K = β(2S · L + 1) the “spin–orbit operator.” Their explicit definition in terms of spherical harmonics can be found in, e.g., Ref. 15, p. 126. The symbols mj and κj are the traditional names of their indices.
Particle creation occurs; i.e., the two sectors do not decouple [H is not block diagonal in the decomposition (31)].
- For every ψ ∈ D, the upper sector is of the formas x → 0 with (uniquely defined) short distance coefficients and particular functions given by(35)(36a)(36b)
- Every ψ ∈ D obeys the IBCand H acts on ψ ∈ D according to(37)(38a)(38b)
Equivalently, the IBC (37) could be written as
for every .
It seems plausible that an analogous IBC Hamiltonian can be set up for Nmax > 1 by applying the same terms on each particle sector.
In our construction of H, one angular momentum sector of , indexed by , gets coupled to the 0-particle sector. If we took the 0-particle sector to have more than one dimension, say instead of , then we could couple several angular momentum sectors listed in (34) to several mutually orthogonal subspaces of the 0-particle sector . However, this mathematical possibility does not seem physically natural.
It would be interesting to investigate also the case |q| ≥ 1. We expect that IBC Hamiltonians exist also in that case because (an angular momentum block of H1, see Sec. III) is known to have multiple self-adjoint extensions also in that case. However, we do not have a proof.
D. Rotational symmetry
The Hamiltonian H provided by Theorem 6 is not rotationally symmetric, for example, because the subspace that plays a special role for H is not invariant under J1 or J2, and, thus, not under the action of the rotation group (more precisely, of its covering group). One might think of coupling all four angular momentum sectors with to the 0-particle sector in a symmetric way, but actually, that does not help.
Let and (H°, D°) be as in Theorems 4 and 6 with any . None of the self-adjoint extensions of (H°, D°) with particle creation is rotationally symmetric.41
The proof is based on the following fact that we also prove in Sec. III.
The only vector in invariant under rotations [i.e., under the representation of the covering group of SO(3)] is the zero vector.
III. PROOFS
Let and the restriction of to . By Theorem 2, is essentially self-adjoint in . Now, Theorem 3 yields the statement of Theorem 1.□
Use Theorems 3 and 5 with Nmax = 1, as in (22), . Since , the only possibilities for D< are D< = {0} and , and since D is dense, only remains. In particular, H< is multiplication by some real constant E00.□
In the following, we will say “angular momentum sector” to . Our construction of the IBC Hamiltonian H proceeds for each angular momentum sector separately. For one sector, the one chosen in (34), we will couple to the 0-particle sector of our mini-Fock space ; all other angular momentum sectors will decouple. That is, H will be block diagonal relative to the sum decomposition
(note that j is determined by κj through ), but not relative to
To this end, we need a self-adjoint extension for every with .
For the three sectors in mentioned in (34) but different from , we choose the distinguished extension, and for those not mentioned there (i.e., with |κj| ≥ 2), the extension is unique. These extensions can be combined to form an extension of H° on all summands but the first in (65). So, it remains to construct the block of H acting in , which is where the coupling between particle sectors takes place. Correspondingly,
with to be determined. For brevity, we set
We regard h as defined on . Another known fact is the following.
For higher angular momentum sectors (|κj| ≥ 2), functions in the domain of the unique self-adjoint extension of are o(r1/2) [because the extension is , and the domain of that contains only o(r1/2) functions by Ref. 43, Proposition 2.4] and, thus, contribute only o(|x|−1/2) in (35).
We will directly consider the more general form (40) of the IBC, which contains (37) as a special case. We define the domain of as follows, containing functions satisfying the IBC (40)
is dense in because (i) in D(h*), there exist functions with arbitrary values of c− and c+, so for , any desired complex number can occur as ψ(0); (ii) since is contained in D(h*) and dense in , the set is dense in . Together, (i) and (ii) imply that is dense.
We now prove that is a symmetric operator on . Let with short distance coefficients c− and c+, and with short distance coefficients d− and d+. Then,
Now, note that h* can be written as h* = −iαr∂r + M(r), where M(r) is a Hermitian operator for each r > 0. Thus, the last two terms of (74) can be written as
Since in the orthonormal basis of , the explicit form of αr is given by (62), any vector with coefficients has
Since by (36), f± has real coefficients relative to Φ±, we have that
Thus,
if (42) holds.
In order to see that is also self-adjoint, it remains to verify that . To this end, we first note that
Any given lies in if and only if there is such that for every ,
If we write again c−, c+ for the short-distance coefficients of ψ(1) and d−, d+ for those of ϕ(1), then condition (88) is equivalent to
The only way this can be true for all is that
and the product in the first line of (94) vanishes. For one thing, we obtain from this an expression for . Moreover, since the product in the first line of (94) consists of one factor depending on ϕ and one depending on ψ, and since the product needs to vanish for every but the second factor will not, the first factor has to vanish for every . As a consequence, ϕ also needs to satisfy the IBC (40), i.e.,
so that we arrive at
and (and, thus, H) is self-adjoint. This completes the proof of Theorem 6.□
Here is an alternative argument for the part after (86), after it has been shown that H is symmetric. While this alternative argument does not show that H is self-adjoint, it shows that H possesses a self-adjoint extension, which suffices for proving Theorem 6. The argument is based on the von Neumann theorem about conjugations (Ref. 45, Theorem X.3), which asserts the following: let be a Hilbert space. An antilinear map [i.e., such that C(αϕ + βψ) = α*Cϕ + β*Cψ] is called a conjugation if it is norm-preserving and C2 = I. Let [A, D(A)] be a densely defined symmetric operator, and suppose that there exists a conjugation C with C(D(A)) ⊆ D(A) and AC = CA. Then, A has equal deficiency indices and, therefore, has self-adjoint extensions.
In our case, we use that the differential expression (64) for h has only real entries. We assume for the argument that the coupling constant g is real; if this is not the case, it can be arranged through a unitary transformation of that merely changes the phase of ψ(0) by the phase of g. So, we take to be complex conjugation of ψ(0) and of the coefficients of relative to . Since the coefficients a1, …, a4 are real, H commutes with C, and the von Neumann theorem applies.
In Ref. 39, the authors established short-distance asymptotics of wave functions for the case of general Coulomb-type potentials (27), very similarly to Lemmas 3 and 4. Having their analog at hand, constructing a similar IBC Hamiltonian for certain parameter ranges of from (27) is reasonably straightforward.
Suppose ψ was a nonzero vector in invariant under the representation of the covering group of SO(3). A rotation (about any axis) through 360° is a particular element g of the covering group that acts on vectors x in as the identity and on spinors as −I with I the identity. Thus, g maps ψ to −ψ, and if ψ is invariant, it must vanish.□
If H were a self-adjoint extension of H° that involves particle creation, then the initial Fock vector (i.e., the Fock vacuum) would evolve by some time t > 0 to a non-vacuum state, i.e., one with nonzero , that would be invariant under rotations. Since rotations do not mix particle number sectors, also by itself would be invariant under rotations. However, by Lemma 1 no such state exists.□
Note added in proof. After the completion of this work, Binz and Lampart posted a preprint46 in which they described a general abstract framework for the construction of IBC Hamiltonians. The one given in Theorem 6 can also be cast in this form.
ACKNOWLEDGMENTS
J.H. gratefully acknowledges the partial financial support by the ERC Advanced Grant “RMTBeyond” under Grant No. 101020331.
AUTHOR DECLARATIONS
Conflict of Interest
The authors have no conflicts to disclose.
Author Contributions
Joscha Henheik: Formal analysis (equal); Investigation (equal); Writing – original draft (equal); Writing – review & editing (equal). Roderich Tumulka: Formal analysis (equal); Investigation (equal); Writing – original draft (equal); Writing – review & editing (equal).
DATA AVAILABILITY
Data sharing is not applicable to this article as no new data were created or analyzed in this study.
REFERENCES
More generally, the emission of a spin- particle by a source of any spin cannot conserve angular momentum because (i) the creation term in the Hamiltonian morally reads with the creation operator of the emitting particle, the creation operator of the emitted particle, and grr′s complex coefficients with s a Dirac spinor index and r and r′ indices referring to another representation space of the rotation group SO(3) or its covering group and (ii) there is no rotation invariant array of coefficients grr′s. In contrast, the emission of a spin-1 particle by a source of spin can conserve angular momentum, as the coefficients gss′μ = γss′μ are rotation invariant.
Although (H°, D°) is rotationally symmetric, since the domain D° is not dense in , the self-adjoint extensions of (H°, D°) with particle creation are not obtained by simply taking the closure. Hence, as we show, rotational invariance (might) get lost.