The theory of two seemingly different quantum/classical approaches to collisional energy transfer and ro-vibrational energy flow is reviewed: a heuristic fluid-rotor method, introduced earlier to treat recombination reactions [M. Ivanov and D. Babikov, J. Chem. Phys. 134, 144107 (2011) https://doi.org/10.1063/1.3576103], and a more rigorous method based on the Ehrenfest theorem. It is shown analytically that for the case of a diatomic molecule + quencher these two methods are entirely equivalent. Notably, they both make use of the average moment of inertia computed as inverse of average of inverse of the distributed moment of inertia. Despite this equivalence, each of the two formulations has its own advantages, and is interesting on its own. Numerical results presented here illustrate energy and momentum conservation in the mixed quantum/classical approach and open opportunities for computationally affordable treatment of collisional energy transfer.
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28 April 2013
Research Article|
April 23 2013
Equivalence of the Ehrenfest theorem and the fluid-rotor model for mixed quantum/classical theory of collisional energy transfer
Alexander Semenov;
Alexander Semenov
Department of Chemistry, Wehr Chemistry Building,
Marquette University
, Milwaukee, Wisconsin 53201-1881, USA
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Dmitri Babikov
Dmitri Babikov
a)
Department of Chemistry, Wehr Chemistry Building,
Marquette University
, Milwaukee, Wisconsin 53201-1881, USA
Search for other works by this author on:
Alexander Semenov
Dmitri Babikov
a)
Department of Chemistry, Wehr Chemistry Building,
Marquette University
, Milwaukee, Wisconsin 53201-1881, USA
a)
Author to whom correspondence should be addressed. Electronic mail: [email protected]
J. Chem. Phys. 138, 164110 (2013)
Article history
Received:
February 26 2013
Accepted:
March 27 2013
Citation
Alexander Semenov, Dmitri Babikov; Equivalence of the Ehrenfest theorem and the fluid-rotor model for mixed quantum/classical theory of collisional energy transfer. J. Chem. Phys. 28 April 2013; 138 (16): 164110. https://doi.org/10.1063/1.4801430
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