We introduce an “inverse method” for solving the time-independent Schrödinger equation. Rather than derive wave functions that are solutions for a given external potential V(r), we ask the inverse question of which V(r) will have a given probability density function P(r). Several examples of ground states in one, two, and three dimensions are presented for both well-known and more exotic probability density functions in position space.

The time-independent Schrödinger equation (TISE) is normally presented to students as an equation to be solved to find the wave function ψ(r) and energy E for a given potential V(r),
(1)
Here, is Planck's constant divided by 2π. The particle of mass m has a pdf (probability distribution function) P(r)=|ψ(r)|2. Unfortunately, except for the well-studied potentials (particle in an infinite well, simple harmonic oscillator,1 Coulomb potential, and delta-function potential2) there are not many V(r) that have exact solutions. This makes giving students a V(r) they have not seen before to solve on homework or exams problematic.

As opposed to the traditional method, we propose an alternative prescription, the “inverse method.” Here, we limit our studies to only V(r) that have at least one bound state and furthermore restrict ourselves to only finding the ground state. Asking the inverse question makes it elementary for instructors or students to construct their own solvable V(r) for the TISE. Namely, given a pdf P(r), find which potential V(r) and energy E in the TISE is needed with ψ(r)=P(r) to give the desired pdf. Our inverse method works for a wavefunction that can be chosen to be a non-negative function. Mathematical requirements for P(r) are given in Sec. II.

We first outline the prescription for the TISE of Eq. (1) in the Cartesian coordinate system. In order to form the three dimensional (3D) potential V(r) for the given 3D pdf P(r), we define an analytic function f(r) such that P(r)=exp(f(r)). We assume we can choose the wavefunction to be real and positive, thereby limiting which problems we can solve. With that assumption,
(2)
Note P(r) must be normalized, namely, P(r)dr=1, with the integral over the domain of the solution. Next, one calculates the gradient f(r) and Laplacian 2f(r). By substituting Eq. (2) in Eq. (1), we thereby obtain the nonlinear differential equation,
(3)
We use Eq. (3) to obtain V(r) that has ψ(r) as the ground state with energy E = E0. Equation (3) also makes it clear that one can choose any zero for the energy. By convention, if V(r) has a finite absolute minimum value, this is usually chosen as the zero of energy. Potentials obtained using our inverse method have a bound state solution for the TISE. Note the normalization factor for P(r) is a constant addition to f(r), and therefore does not affect the calculation of V(r)E.
When students are first introduced to the TISE, it is in 1D, making our inverse method simple enough to give students a new problem they have not yet seen in order to test their understanding of homework or exams. Namely, students only have to differentiate a given f(x)=ln(P(x)) twice to obtain in 1D,
(4)

For beginning students, instructors can describe sufficient mathematical constraints. First, P(r) should be continuous as well as twice continuously differentiable. Since P(r) is a pdf, it must be normalized. It is permissible for P(r) to be zero on a subset of measure zero, including approaching zero at infinity, in which case at those points f(r) can be undefined.

For more advanced students, less restrictive mathematical constraints than in the previous paragraph may be described. Our inverse method works only when the ground state wavefunction ψ(r) can be chosen to be real, which is possible if the TDSE (time dependent Schrödinger equation) has time reversal invariance. For example, the inverse method will not work for a charged particle in a magnetic field. The method works if f(r) is twice piecewise differentiable, in which case the first and second derivatives need not be continuous when approaching a boundary between adjacent regions. For the piecewise differentiable case, note the energy E in Eq. (3) must be the same in all regions, which may require a constant shift added to the potential in some regions.

Exact solutions for example 1D, 2D, and 3D pdfs in real space are obtained and explained in this section. We implemented our inverse method to obtain solutions of the TISE both for some well-known pdfs and some more exotic pdfs. Additional analysis of some of these pdfs is in Ref. 3.

The inverse method provides a way for students to be assigned to find the ground state of the TISE for pdfs and potentials they have not yet seen. Students can either be asked to create or be given their own f(x) or P(x), with P(x)=exp[f(x)]. Then, using the inverse method, students can be asked to calculate the appropriate V(x) and ground state energy. Figure 1 shows an example. We have chosen
(5)
with A the normalization constant here found by numerical integration to be A0.028202 [see Fig. 1(a)]. By forming f(x)=ln[P(x)], differentiating twice, and using Eq. (4), we find V(x)E shown in Fig. 1(b). We have chosen the zero of energy to be the ground state energy. For advanced classes, symbolic differentiation can be requested, as was done here, giving the rather complicated corresponding V(x)E provided in Ref. 3. One could also ask students to (perhaps numerically) calculate E0 if the zero of energy is chosen to be the absolute minimum value of V(x). For exams and simpler homework, a less complicated P(x) or f(x) could be given.
Fig. 1.

An example of the inverse method suitable for assigning on homework or exams. (a) The 1D pdf in Eq. (5) is shown. (b) The associated V(x) with 2/4m=1. The zero of energy is chosen as the ground state energy. Numerically, we find the absolute minimum V(xmin)=19.692/4m at xmin=2.042.

Fig. 1.

An example of the inverse method suitable for assigning on homework or exams. (a) The 1D pdf in Eq. (5) is shown. (b) The associated V(x) with 2/4m=1. The zero of energy is chosen as the ground state energy. Numerically, we find the absolute minimum V(xmin)=19.692/4m at xmin=2.042.

Close modal

We also solved the inverse problem for five additional 1D distributions: Gaussian, Gumbel, Lorentzian (Cauchy), logistic, and student's t pdfs. The results are displayed in Table I. These five pdfs have the domain x[,+]. Additional analysis for each 1D pdf is in Ref. 3.

TABLE I.

Five normalized 1D pdfs, P(x) with <x<, that satisfy the TISE together with their potentials V(x) and ground state energy E0. The mode of these five pdfs is x0. The zero of energy is chosen as the minimum value of V(x). The ground state energy E0 is written both in terms of the pdf parameters (fourth column) and in terms of ω=k/m ( fifth column) with the effective spring constant k from the second-order term of a Taylor expansion of V(x) about its absolute minimum value. To the best of our knowledge, this is the first solution of the TISE ground state pdf for the last four listed V(x) potentials.

Pdf P(x) V(x) with [24m=1] E0[24m=1] E0
Gaussian  1σ2πe1/2(xx0/σ)2  (xx0)22σ4  1σ2  12ω 
Lorentzian(Cauchy)  1πγ[γ2(xx0)2+γ2]  6(xx0)2[(xx0)2+γ2]22(xx0)2+γ2+2γ2  2γ2  14ω 
Gumbelmax  1βexp[((xx0β)+e(xx0/β))]  12β2(1e(xx0/β))2+32β2e(xx0β)β2  32β2  38ω 
Logistic  14ssech2(xx02s)  1s2tanh2(xx02s)  12s2  122ω 
Student's t  Γ(ν+12)νπΓ(ν2)(1+(xx0)2ν)ν+1/2  (ν+1)[(ν+3)(xx0)22ν]2(ν+(xx0)2)2+ν+1ν  ν+1ν  ω2ν+1ν+7 
Pdf P(x) V(x) with [24m=1] E0[24m=1] E0
Gaussian  1σ2πe1/2(xx0/σ)2  (xx0)22σ4  1σ2  12ω 
Lorentzian(Cauchy)  1πγ[γ2(xx0)2+γ2]  6(xx0)2[(xx0)2+γ2]22(xx0)2+γ2+2γ2  2γ2  14ω 
Gumbelmax  1βexp[((xx0β)+e(xx0/β))]  12β2(1e(xx0/β))2+32β2e(xx0β)β2  32β2  38ω 
Logistic  14ssech2(xx02s)  1s2tanh2(xx02s)  12s2  122ω 
Student's t  Γ(ν+12)νπΓ(ν2)(1+(xx0)2ν)ν+1/2  (ν+1)[(ν+3)(xx0)22ν]2(ν+(xx0)2)2+ν+1ν  ν+1ν  ω2ν+1ν+7 

The first row in Table I is the well-known Gaussian pdf in 1D with standard deviation σ. The corresponding potential is the simple harmonic oscillator (SHO or quadratic) potential with the potential minimum at x = x0 with V(x0)=0. The pdf P(x) is the ground state probability distribution. The ground state energy E0=2/4mσ2, which is more commonly written as E0=(1/2)ω. The angular frequency is ω=k/m, with V(x)=(1/2)k(xx0)2 with k the spring constant of the SHO. Note the SHO relationship σ2=(xx0)2=/2mω.

Table I lists four additional common 1D pdfs. A Gumbel pdf is an extreme value type I distribution and is different for maximum or minimum extreme values.4 We analyze only the Gumbel pdf for maximum extreme values, leaving the Gumbel minimum extreme value pdf as an exercise for the reader. Implementing our approach for the Gumbel (maximum extreme value) pdf in 1D, we found the corresponding potential VGbl(x) has a minimum at xmin=x0βln(2). Here, we have chosen VGbl(xmin)=0, and the energy associated with the ground state is found to be E0=32/8mβ2. The Lorentzian (or Cauchy) pdf has the corresponding potential with VCauchy(x±)2/2mγ2. VCauchy(x) has a minimum at xmin=x0 with VCauchy(xmin)=0, and it has maxima located at xmax=x0 ± γ2 with the value VCauchy(xmax)=22/3mγ2. Nevertheless, we have found the single bound state for the VCauchy(x) potential, with the ground state energy E0=2/2mγ2. The potential associated with the logistic pdf is zero at its minimum x = x0 and achieves its maximum 2/4ms2 as x±. We found the ground state energies (in units where 2/4m=1) to be 1/σ2, 2/γ2, 3/2β2, and 1/2s2 for the Gaussian, Lorentzian, Gumbel, and logistic distributions, respectively. We also analyzed the student's t distribution, which for ν=1 is the Cauchy pdf with γ=1. As ν the student's t pdf approaches the Gaussian pdf with σ=1. The exact potentials V(x) and ground state energy E0 for each of these 1D pdfs are provided in Table I where column 3 contains the associated potentials for the pdfs in column 2.

Solutions to Eq. (3) in higher dimensions are also easily found using the inverse prescription. We briefly present two pdfs in 2D and one in 3D. Additional details are included in Ref. 3.

1. 2 D separable pdf: Gumbel and Gaussian

Consider traditional separable pdfs in 2D Cartesian coordinates, P(x,y)=Px(x)Py(y). Then, one has f(x,y)=ln[P(x,y)]=fx(x)+fy(y), and hence a potential V(x,y)=Vx(x)+Vy(y). The same result generalizes to higher dimensions and to any other separable set of coordinates. We used Eq. (3) to explicitly get exact solutions for the pdfs for a combined Gaussian + Gumbel in 2D Cartesian coordinates (x, y). The domain is (x,y)[,+]×[,+]. We choose to study a 2D pdf using the Gumbel pdf on x and Gaussian pdf on y coordinates, in particular PGblian(x,y)=PGumbel(x)×PGaussian(y). Explicitly,
(6)
Here, x0 and y0 are the mode of PGumbel(x) and PGaussian(y), respectively. The symbol β is the scale parameter for the pdf PGumbel(x). The 2D analytic function associated with the pdf in Eq. (6) has the form fGblian(x,y)=fGumbel(x)+fGaussian(y). Using the gradient and the Laplacian of the function fGblian(x,y) in Eq. (3) in 2D, the potential for the pdf in Eq. (6) is
(7)
We have chosen the zero of energy so V(xmin,ymin)=0. The ground state energy for the 2D pdf PGblian(x,y) is
(8)
which is the sum of the two 1D results in Table I. Note here the two spring constants kx and ky from a 2D Taylor expansion about (xmin, y0) are different. Define ωx=kx/m and ωy=ky/m. Explicitly, from Table I, ωx=/mβ2 so the spring constant kx=mωx2=2/mβ4. Example plots are shown in Fig. 2.
Fig. 2.

(a) The 2D pdf PGblian(x,y)=PGumbel(x)×PGaussian(y) with β = 1, σ = 1, x0=0, and y0=0. (b) The associated 2D potential VGblian(x,y)=VGumbel(x)+VGaussian(y) with units 2/4m=1. The ground state for this 2D system, from Table I with 2/4m=1, is E0=(1/σ2)+(3/2β2) which for σ=β=1 gives E0=5/2.

Fig. 2.

(a) The 2D pdf PGblian(x,y)=PGumbel(x)×PGaussian(y) with β = 1, σ = 1, x0=0, and y0=0. (b) The associated 2D potential VGblian(x,y)=VGumbel(x)+VGaussian(y) with units 2/4m=1. The ground state for this 2D system, from Table I with 2/4m=1, is E0=(1/σ2)+(3/2β2) which for σ=β=1 gives E0=5/2.

Close modal

We could have chosen P(x) and P(y) as any of the pdfs in Table I. Then, the associated V(x,y)=V(x)+V(y) and the ground state energies are the sum of the two associated ground state energies in Table I. Although the pdfs in Table I all are 1D and have a single maximum in P(x), these conditions are not a requirement, as seen in Fig. 1. Very convoluted pdfs, including multimodal P(r), can be constructed that with the inverse problem prescription gives a very complicated V(r).

2. 2D non-separable pdf

We study one 2D case with a non-separable pdf. Reference 3 discusses a non-separable case for a 2D simple harmonic oscillator. Here, we study a pdf of the following form:
(9)
for (x,y)[,]×[,]. Calculating the Laplacian and gradient of the function fnon(x,y)=ln[Pnon(x,y)] and using Eq. (3) gives the rather complicated potential,
(10)
We find numerically the normalization constant Nnon=0.285, and the absolute minimum of Eq. (10) is Vnon(0,1.18)E=45.12/4m. Consequently, the energy difference between the minimum of Vnon(x,y) and the ground state energy is 45.12/4m. Note the minimum being at x = 0 is from the Vnon(x,y)=Vnon(x,y) symmetry of Eq. (10). See Fig. 3 for plots of Eqs. (9) and (10).
Fig. 3.

(a) The pdf Pnon(x,y) of Eq. (9). (b) A plot of Vnon(x,y) from Eq. (10), with the choices 2/4m=1 and E0=0.

Fig. 3.

(a) The pdf Pnon(x,y) of Eq. (9). (b) A plot of Vnon(x,y) from Eq. (10), with the choices 2/4m=1 and E0=0.

Close modal

3. 3D simple harmonic oscillator and hydrogen atom

Consider a 3 D pdf that only depends on the radial component r=x2+y2+z2 and assume a pdf P3D(r)=N3Dexp[2(r/ap)p]. Here, p > 0 is a fixed dimensionless real number, and ap is a parameter with units of length. We have r[0,] and chose the normalization N3D=(0P3D(r)r2dr)1. In Eq. (3), only the radial partial derivatives of the Laplacian and gradient are non-zero because the associated f3D(r)=2(r/ap)pln(N3D) does not depend on the θ or ϕ spherical coordinates. Equation (3) yields
(11)
with the individual results for f and 2f given in Ref. 3. Reference 3 also gives a number of examples and associated plots for various values of p. Two values for p are for potentials students may have already studied.
For p = 2 from Eq. (11), we can write
(12)
with the definition of the angular frequency ω=2/ma22. From Eq. (12), we see that p = 2 is the well-studied problem of a 3D simple harmonic oscillator with identical spring constants along each of the Cartesian coordinates. The ground state energy is hence three times the 1D Gaussian pdf value listed in Table I.
For p = 1, one obtains the results of the ground state of the hydrogen atom. In the MKS system, let m be the mass of an electron, e the charge of an electron, and ϵ0 the vacuum permittivity. In this case, a1=aB with the Bohr radius aB=4πϵ02/me20.529 Å. With p = 1 from Eq. (11), we can write
(13)
Hence, for p = 1, one has P3D(r)=N3Dexp[r/aB] as the radial component of the ground state wavefunction for a hydrogen atom.

In summary, we have introduced an inverse problem methodology to solve the time-independent Schrödinger equation (TISE). The inverse method for the TISE is simple enough to be taught to students the first time they are introduced to the TISE. The introduced prescription gives a wide class of new solutions for bound states of the TISE and works in any dimension. We have illustrated the method by obtaining solutions for six 1D pdfs with the domain x[,+], see Table I for five common 1D pdfs. Solutions for the 1D pdfs Rayleigh and Chi with the domain x[0,+] as well as the Beta and Kumaraswamy pdfs with the domain x[0,1] are documented in Ref. 5. In this paper, our inverse method was also illustrated for select 2D and 3 D pdfs.

Two generalizations can be envisioned. The inverse method prescription should work for a pdf that is an excited state of the TISE, using an analogue of the fixed-node approximation for locations where P(x) = 0. One can also generalize the inverse problem to the TDSE, which corresponds to two coupled nonlinear differential equations6,7 as derived, for example, using the Fisher information theory.8–11 The inverse problem then uses an Ansatz for P(r,t) as well as the action. Note the two coupled nonlinear equations derived using Fisher information are the analogue mathematically of Bohm's formulation of quantum mechanics.12,13 Some implementation of the inverse method for the TDSE is in Ref. 5.

The project reported here was motivated by the ability to change the potential V(r) for an atomic gas Bose–Einstein condensate (BEC). Painted potentials for a BEC have been reported.14 A cloud-based BEC device with a programmable ‘painted’ V(r) was recently introduced by the company Infleqtion.15 The BEC state measured is the ground state associated with V(r), motivating concentrating on the inverse method for only the ground state of the TISE. For the BEC, the underlying equation is the non-linear Schrödinger equation, namely, the Gross–Pitaevskii equation (GPeq), which takes into account atomic interactions.16 In fact, the inverse method was introduced to provide a solution for the GPeq.5,17–19 Exact solutions for the GPeq obtained with the inverse method can also be used to validate numerical codes, such as the GPeq multigrid renormalization method.20 The inverse method will also work in other cases where the GPeq may be valid, for example for including ψ-dark-matter21 in large-scale structure investigations of the universe.

The authors thank Ms. A. Tingle, Dr. D. Dahl, and Profs. H. de Raedt, G. Rupak, and Y. Koshka for useful discussions. M.A.N. gratefully acknowledges partial support from Grant No. DOE DE-SC0024286.

The authors have no conflicts to disclose.

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Supplementary Material