In a recent article, in this journal,1 a mapping between the electrostatic potential in three dimensions and the one-dimensional Schrödinger equation was obtained through a simple transformation, resulting in a straightforward determination of the ground state wave functions and associated energies. That paper employs a planar symmetry that displays a direct relation with the one-dimensional Schrödinger equation. Here, we show that the transformation given in Ref. 1 also works for the three dimensional magnetostatic case. Thus, using the same transformation a student can directly obtain the ground state wave function using the magnetic vector potential A.

We know that in order to find the magnetostatic field B we need to solve the set of (three) Poisson equations2 

(1)

where B = ∇ × A and J is the current density. If we consider the problem of an odd...

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