The mean energy per excitation wavelength of e.m. radiation propagated along a lossless uniform wave guide is found to be w = Qμ, Q being independent of frequency for a given amplitude of the longitudinal field intensity, mode of the field, and structure of the guide. The frequency μ and the group velocity vg of the radiant energy are related by the equation μ/μc  = [1 − (vg/c)2]12 where μc = c/λc denotes the frequency at cutoff, and λc the excitation wavelength at cutoff. This equation permits one to put
. The amplitudes of the field intensities are chosen such that Q equals Planck's constant h. Applying the mass-energy relation, the term c = hc/λc = m0c2 may be interpreted as the “potential” (= rest) energy of the quantum and m0 as the rest mass. The momentum p associated with is found to be p = h/λg, λg being the wavelength along the guide. When radiant energy passes from one guide into another one of different cross-sectional structure via a tapered piece of wave guide, a partial conversion of “potential” to “kinetic” energy, and vice versa, occurs along the tapered section. In the case of TEM waves, which, however, can only be supported in a guide of infinite transverse dimensions, the group velocity becomes c and the rest mass zero.
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